How about:
def median(lst):
lst = sorted(lst)
inner = lst[(len(lst) - 1) // 2 : (len(lst) + 2) // 2]
if len(inner) > 1:
return sum(inner) / 2.
else:
return inner[0]
--Scott David Daniels [EMAIL PROTECTED] -- http://mail.python.org/mailman/listinfo/python-list
