Re: updating locals() and globals() (WAS: How do I do this? (eval() on the left hand side))

[Steven Bethard]

Jeff Shannon wrote:
(Note also that functions which use exec cannot use the static namespace 
optimization, and thus tend to be *much* slower than normal functions 
(in addition to being a huge security problem).  I don't know, however, 
whether locals() can update the local namespace in such un-optimized 
functions.
Doesn't look like it:
>>> exec """\
... def f():
...     x = 3
...     locals()['x'] = 4
...     print x
... """
>>> f()
3
Steve
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