Terry Reedy wrote:
As far as I know, apply(func, args) is exactly equivalent to func(*args).
After playing around a bit I did find one difference in the errors they can create.
def count():
... yield 1
...
apply(f, count())
Traceback (most recent call last): File "<stdin>", line 1, in ? TypeError: apply() arg 2 expected sequence, found generator
f(*count())
Traceback (most recent call last): File "<stdin>", line 1, in ? TypeError: len() of unsized object
No question that they report different errors in the face of being given unsupported input.
That led me to the following
<snip>
blah = Blah() len(*blah)
6
apply(len, *blah)
Traceback (most recent call last): File "<stdin>", line 1, in ? TypeError: len() takes exactly one argument (6 given)
Is that difference a bug?
They do two different things. I think you have a spurious * in the call to apply. The apply above is equivalent to
>>> len('H', 'e', 'l', 'l', 'o', '!')Which gives the same error:
Traceback (most recent call last): File "<stdin>", line 1, in ? TypeError: len() takes exactly one argument (6 given)
If the * is removed, it works correctly:
>>> apply(len, blah) 6 -- Benji York [EMAIL PROTECTED]
-- http://mail.python.org/mailman/listinfo/python-list
