On Thu, 30 Dec 2004 12:06:31 -0800, Scott David Daniels
<[EMAIL PROTECTED]> wrote:
>Here's one way: # (Make __iter__ an iterator)
>Py> class R1(object):
> def __init__(self, data):
> self.data = data
> self.i = len(data)
> def __iter__(self):
> while self.i > 0:
> self.i -= 1
> yield self.data[self.i]
Thanks to everyone for their responses, but it still doesn't work re
returning next() method:
>>>
class R3:
def __init__(self, d):
self.d=d
self.i=len(d)
def __iter__(self):
d,i = self.d, self.i
while i>0:
i-=1
yield d[i]
>>> p=R3('eggs')
>>> p.next()
Traceback (most recent call last):
File "<interactive input>", line 1, in ?
AttributeError: R3 instance has no attribute 'next'
>>> dir(p)
['__doc__', '__init__', '__iter__', '__module__', 'd', 'i']
>>> list(p)
['s', 'g', 'g', 'e']
>>>
I tried all the methods advised by you and other posters and they do
return an object with __iter__, but not with the next method.
What's strange is that when it comes to function, it does return
the .next method:
def rev(d):
for i in range (len(d)-1, -1, -1):
yield d[i]
>>> o=rev('eggs')
>>> o
<generator object at 0x0120DF58>
>>> dir(o)
['__class__', '__delattr__', '__doc__', '__getattribute__',
'__hash__', '__init__', '__iter__', '__new__', '__reduce__',
'__reduce_ex__', '__repr__', '__setattr__', '__str__', 'gi_frame',
'gi_running', 'next']
>>> o.next()
's'
>>> o.next()
'g'
>>> o.next()
'g'
>>> o.next()
'e'
The function returns 'generator object', as shown above,
while p is a class instance:
>>> p
<__main__.R3 instance at 0x0123CA58>
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