Sean wrote:
My problem is that many of the example scripts are run on Linux
machines and I am using Win XP Pro.  Here is a specific example of what
is confusing me.  If I want to open a file from the dos prompt in some
script do I just write the name of the file I want to open (assuming it
is in the same directory) after the script name?
such as

c:\some_script.py some_text_file.txt

It's unclear to me what you want to do here. If your some_script.py looks like:


import sys
f = file(sys.argv[1])

then yes, you can call some_script.py as above, and the file will be readable from the 'f' file object.


Does piping work the same way in dos as it does on a linux machine?

Mostly:

[D:\Steve]$ type test.py
import sys
for i, line in enumerate(sys.stdin):
    sys.stdout.write("%i:%s" % (i, line))

[D:\Steve]$ type input.txt
A
B
C
D

[D:\Steve]$ python test.py < input.txt
0:A
1:B
2:C
3:D

[D:\Steve]$ python test.py > output.txt
Z
Y
X
^Z
^Z

[D:\Steve]$ type output.txt
0:Z
1:Y
2:X

[D:\Steve]$ python test.py < input.txt > output.txt

[D:\Steve]$ type output.txt
0:A
1:B
2:C
3:D

[D:\Steve]$ type input.txt | python test.py
0:A
1:B
2:C
3:D


Note however, that you may run into problems if you don't explicitly call python:


[D:\Steve]$ test.py < input.txt
Traceback (most recent call last):
  File "D:\Steve\test.py", line 2, in ?
    for i, line in enumerate(sys.stdin):
IOError: [Errno 9] Bad file descriptor

And last but not least, is there a way to do this all from IDLE?

What exactly do you want to do? You can certainly type something like:

    f = file('input.txt')

in IDLE to get access to the 'input.txt' file...

Steve
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