On Fri, 2005-01-07 at 02:06, Josh wrote: > Peter, > > Thank you for the rookie correction. That was my exact problem. I > changed the address to use forward slashes and it works perfect. I did > not know that a backslash had special meaning within a string, but now > I do! Thanks again
There's another common mistake you might want to head off now, too. Consider the following program: -------- directory = r"c:\mydata" datafilename = "something.txt" datafile = open(directory + datafilename,"r") --------- It's very common for this to happen, usually when the paths are originally written with trailing slashes then changed to not have them later. Rather than saying "all paths must have trailing slashes", manually formatting in slashes, or other platform-specific uglyness, consider using the os.path module to take care of it: -------- import os directory = r"c:\mydata" datafilename = "something.txt" datafile = open(os.path.join(directory,datafilename),"r") -------- This will work on any platform (so long as the literal paths are correct) and will work no matter whether or not there are trailing path separators on the input strings. os.path.join can take more than two arguments, too. os.path has lots of other handy tools, so I strongly recommend checking it out. -- Craig Ringer -- http://mail.python.org/mailman/listinfo/python-list
