vincent wehren wrote:
rbt wrote:
If I have a Python list that I'm iterating over and one of the objects in the list raises an exception and I have code like this:
try: do something to object in list except Exception: pass
Does the code just skip the bad object and continue with the other objects in the list, or does it stop?
Thanks
Fire up a shell and try:
>>> seq = ["1", "2", "a", "4", "5", 6.0] >>> for elem in seq: .... try: .... print int(elem) .... except ValueError: .... pass
and see what happens...
-- Vincent Wehren
I suspect the more recent versions of Python allow a much more elegant solution. I can't remember precisely when we were allowed to use continue in an except suite, but I know we couldn't in Python 2.1.
Nowadays you can write:
Python 2.4 (#1, Dec 4 2004, 20:10:33) [GCC 3.3.3 (cygwin special)] on cygwin Type "help", "copyright", "credits" or "license" for more information. >>> for i in [1, 2, 3]: ... try: ... print i ... if i == 2: raise AttributeError, "Bugger!" ... except AttributeError: ... print "Caught exception" ... continue ... 1 2 Caught exception 3 >>>
To terminate the loop on the exception you would use "break" instead of "continue".
regards Steve -- Steve Holden http://www.holdenweb.com/ Python Web Programming http://pydish.holdenweb.com/ Holden Web LLC +1 703 861 4237 +1 800 494 3119 -- http://mail.python.org/mailman/listinfo/python-list
