Yes, Mark, I came up with almost the same code (after reading back old
answers from this list):
def flatten(seq):
for x in seq:
if hasattr(x, "__iter__"):
for subx in flatten(x):
yield subx
else:
yield x
def count_item(data):
return len([(i,x) for i, x in enumerate(flatten(data))])
data = [[1,5,2],8,4]
print count_item(data)
Thanks everybody.
"Mark McEahern" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> It's me wrote:
>
> >Okay, I give up.
> >
> >What's the best way to count number of items in a list [that may contain
lists]?
> >
> >
> a = [[1,2,4],4,5,[2,3]]
>
> def iterall(seq):
> for item in seq:
> try:
> for subitem in iterall(item):
> yield subitem
> except TypeError:
> yield item
>
> all = [x for x in iterall(a)]
> print len(all)
>
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