On 2006-07-21 21:05:22, Josiah Manson wrote: > I found that I was repeating the same couple of lines over and over in > a function and decided to split those lines into a nested function > after copying one too many minor changes all over. The only problem is > that my little helper function doesn't work! It claims that a variable > doesn't exist. If I move the variable declaration, it finds the > variable, but can't change it. Declaring the variable global in the > nested function doesn't work either. > > But, changing the variable in the containing scope is the whole purpose > of this helper function. > > I'm new to python, so there is probably some solution I haven't > encountered yet. Could you please suggest a nice clean solution? The > offending code is below. Thanks.
I'm no Python specialist, so here's just some guesses... I don't know how to make variables known inside the inner function. It seems just using the names there overrides the outside names. It also seems that local variables are in some kind of dictionary; so maybe you can access them through that somehow. One other solution (a bit ugly) would be to make this a class with two static methods (breakLine and _addTok) and two static attributes (_ls and _tok). Still another (also ugly) would be to pass both tok and ls to addTok() and pass tok back out again. (I think ls doesn't have to be passed back, because it is a list and so its data gets modified. tok's data doesn't get modified, so local changes don't propagate to the outside.) Gerhard -- http://mail.python.org/mailman/listinfo/python-list
