Re: building lists of dictionaries

[Ernesto García García]

> parinfo = [{'value':0., 'fixed':0, 'limited':[0,0], 'limits':[0.,0.]}]*6

With this, you are creating a list with 6 references to the same list. 
Note that the left operand of '*' is evaluated only once before 
"multiplying" it six times.

Regards,
Tito
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