Paul McGuire wrote: > "Paul McGuire" <[EMAIL PROTECTED]> wrote in message > news:[EMAIL PROTECTED] > > "Chaos" <[EMAIL PROTECTED]> wrote in message > > news:[EMAIL PROTECTED] > > > > > > > > > myCol = (0.3 * image.GetRed(thisX, thisY)) + (0.59 * > > > image.GetGreen(thisX, thisY)) + (0.11 * image.GetBlue(thisX, thisY)) > > > if myCol < darkestCol: > > > darkestCol = myCol > > > possX = thisX > > > possY = thisY > > > > > > > Psyco may be of some help to you, especially if you extract out your myCol > > expression into its own function, something like: > > > > def darkness(img,x,y): > > return (0.3 * img.GetRed(x,y)) + (0.59 * img.GetGreen(x,y)) + (0.11 * > > img.GetBlue(x,y)) > > > <snip> > > Even better than my other suggestions might be to write this function, and > then wrap it in a memoizing decorator > (http://wiki.python.org/moin/PythonDecoratorLibrary#head-11870a08b0fa59a8622 > 201abfac735ea47ffade5) - surely there must be some repeated colors in your > image. > > -- Paul
Its not only finding the darkest color, but also finding the X position and Y Position of the darkest color. -- http://mail.python.org/mailman/listinfo/python-list