why don't you iterate over the list instead of indices? for elem in L: print elem,
you don't need the 0 when you call range: range(0, n) == range(n) the last element of a range is n-1: range(n)[-1] == n-1 you don't need while to iterate backwards. the third argument to range is step. range(n-1, -1, -1) == [n-1, n-2, n-3, ..., 1, 0] [EMAIL PROTECTED] wrote: > Hi, > > I have a small problem with my function: printList. I use print with a > ',' . Somehow the last digit of the last number isn't printed. I wonder > why. > > import random > > def createRandomList(param): > length = param > > a = [] > """" creating random list""" > for i in range(0,length): > a.append(random.randrange(100)) > return a > > def printList(param): > #doesn't work > #2 sample outputs > # 30 70 68 6 48 60 29 48 30 38 > #sorted list > #6 29 30 30 38 48 48 60 68 7 <--- last character missing > > #93 8 10 28 94 4 26 41 72 6 > #sorted list > #4 6 8 10 26 28 41 72 93 9 <-- dito > > > for i in range(0,len(param)): > print a[i], > #works > #for i in range(0,len(param)-1): > # print a[i], > #print a[len(param)-1] > > > if __name__ == "__main__": > length = 10 > a = createRandomList(length) > printList(a) > > for j in range(1,len(a)): > key = a[j] > i = j-1 > while i > -1 and a[i]>key: > a[i+1] = a[i] > i = i-1 > a[i+1] = key > > print "\n sorted list" > printList(a) -- http://mail.python.org/mailman/listinfo/python-list
