On 7 Aug 2006 13:52:16 -0700, Hitesh <[EMAIL PROTECTED]> wrote: > > I have a small script here that goes to inside dir and sorts the file > by create date. I can return the create date but I don't know how to > find the name of that file... > I need file that is not latest but was created before the last file.
I notice that your path is UNC & windows, if you are running this on a windows platform only you could let the windows DIR do the work for you. >>> import os >>> i,o,e = os.popen3('dir /O-D /A-D /B') >>> o.readlines()[1].strip() 'dnscheck.html' I would put a try:except around the o.readlines().... bit in case there is only 0 or 1 file in the directory. Hints: c:\> dir /? (enter) >>> i,o,e = os.popen3('dir /O-D /A-D /B) >>>o.readlines() ['recover.tbl\n', 'dnscheck.html\n', 'v3changes.txt\n', 'V3todo.txt\n', 'fupdates.pyc\n', 'Auth_db.pyc\n'] HTH :) -- http://mail.python.org/mailman/listinfo/python-list