jojoba wrote:
> hello!
>
> i am trying to come up with a simple way to access my values in my
> nested python dictionaries
>
> here is what i have so far, but i wanted to run it by the geniuses out
> there who might see any probems with this...
> here is an example:
>
> +++++++++++++++++++++++++++++++++++++++
> def SetNewDataParam(Data, paramPath, NewData):
> ParamList = paramPath.split('/')
> numParams = len(ParamList)
> for i in range(0, numParams):
> if i != (numParams-1):
> Data = Data[ParamList[i]]
> else:
> Data[ParamList[i]] = NewData
>
when I add here
ret Data
>
> Data = {'a':{'b':{'c':1}}}
> paramPath = 'a/b/c'
> NewData = 666
> SetNewDataParam(Data, paramPath, NewData)
and change this to
ret = SetNewDataParam(Data, paramPath, NewData)
print ret
the shell returns me
{'c': 666}
> +++++++++++++++++++++++++++++++++++++++
>
>
> so it works!
> when i do:
> print Data, i get
> {'a':{'b':{'c':666}}}
>
>
> but i am hesistant to be throwing around dictionary references
> how is this working????
> shouldn't my line above:
> Data = Data[ParamList[i]]
> screw up my original Data dictionary
>
> Thanks to anyone with comments on this
> By the way, i love the idea of using tuples as keys, but my code is so
> far along that i dont wanna switch to that elegant way (maybe on a
> future project!)
> take care,
> jojoba
| would use a recursive approach for this - given that you have a sort
of recursive datastructure:
py> def SetNewDataParam2(Data, NewData):
... if type(Data[Data.keys()[0]]) == type(dict()):
... SetNewDataParam2(Data[Data.keys()[0]], NewData)
... else:
... Data[Data.keys()[0]] = NewData
...
... return Data
py> Data = {'a':{'b':{'c':1}}}
py> NewData = 666
py> ret = SetNewDataParam2(Data, NewData)
py> print ret
{'a': {'b': {'c': 666}}}
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