thanks - that's the trick.
On 8/17/06, Tim Chase <[EMAIL PROTECTED]> wrote: > Looks like you need to be using "raw" strings for your > replacements as well: > > s = re.sub(r'([A-Z]+)([A-Z][a-z])', r"\1_\2", s) > s = re.sub(r'([a-z\d])([A-Z])', r"\1_\2", s) > > This should allow the backslashes to be parsed as backslashes, > not as escape-sequences (which in this case are likely getting > interpreted as octal numbers) > > -tkc > -- http://mail.python.org/mailman/listinfo/python-list
