[...]Hello all,
I have a misunderstanding about dynamic class methods. I don't expect this behavior:
In [2]: class test: ...: def __init__(self, method): ...: self.method = method ...: self.method() ...:
In [3]: def m(self): print self ...:
TypeError: m() takes exactly 1 argument (0 given) -----------------------------------------------------------------------------
Why doesn't m get the implicit self parameter in the self.method() call? How would I make it a proper member of the class, so that a self.method() call would work with the above "m" function?
m is a function. When you assign it to self.method, it's still a function. You don't create a new method that way; all you have is a new attribute called 'method' containing the function.
To add m as a new method to the *class*, do this:
>>> class test: ... def __init__(self, method): ... self.__class__.method = method ... self.method() ... >>> def m(self): print self ... >>> test(m) <__main__.test instance at 0x0192ED78> <__main__.test instance at 0x0192ED78> >>>
To add m as a new method to the *instance*, use new.instancemethod, as Diez B. Roggisch already pointed out.
HTH,
-- Hans Nowak http://zephyrfalcon.org/
-- http://mail.python.org/mailman/listinfo/python-list
