[EMAIL PROTECTED] wrote:
> lets say you want a generic numerical algorithom like sum
>
> Ruby
>
> def sum lst
> lst.inject(0){|total,current| total*current}
> end
>
> Java // i dont know if there is a numeric super class for numbers
>
> class Sum{
> public static int sum(int[] lst){
> int total = 0;
> for(int current : lst){
> total+=current;
> }
> return total;
> }
> // repeat for all other number types
> }
Any more to add? Your question is not exactly clear. Are you asking how
to do higher order procedures in Python? Here's sum as a higher-order
procedure... It sums the numbers from a to b (or any thing that can be
compared and added with "<" and "+").
def Sum(term, next, a, b):
if(a > b):
return 0
else:
return (term(a) + (Sum(term, next, next(a), b)
This function takes two functions (term and next) and two objects (in
our case numbers) representing the range to sum across. Now let's say
you want to add the numbers 1 through 10. The term for the summation
would just be the number, so the term function would simply be a
function called identity, and could be defined as
def identity(x):
return x
To get the next term, we are just adding one each time (i.e. 1, 2, 3,
4, ...). So our next function is
def increment(x):
return x += 1
Then we call Sum(identity, increment, 1, 10), and we get 1 + 2 + 3 + 4
+ and so on.
Now what if you wanted the sum of the CUBES of 1 through 10? Easy, we
replace the term function with a function cube(x) that returns x*x*x.
Sum(cube,increment,1,10)
Hence each term in our summation is the cube, but we are still
incrementing by one each time, so we get (1^3 + 2^3 + 3^3 + 4^3 + ...)
Similarly we can change the next function to skip certain number, meet
certain requirement, do some tranformation, whatever. The fact that
python accept and uses functions as parameters to other functions is
awesome in terms of power, but it can get a little mind boggling
sometimes.
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