[EMAIL PROTECTED] wrote:
> Another way might be to sort by absolute value:
>
> intermed = [(abs(v), v) for v in foo]
> intermed.sort()
> intermed[0][1]
It is slightly simpler if you use sorted (assuming a recent enough Python):
intermed = sorted(foo, key=abs)
print intermed[0]
The sorted list is of course the best way if you want to find not just one
value but a group, e.g. the n nearest to 0.
For nearest to a non-zero value v the version with sorted becomes:
intermed = sorted(foo, key=lambda x:abs(x-v))
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