On 2006-10-04, Paul Rubin <http> wrote: > "LaundroMat" <[EMAIL PROTECTED]> writes: >> def f(var=1): >> return var*2 >> >> What value do I have to pass to f() if I want it to evaluate var to 1? >> I know that f() will return 2, but what if I absolutely want to pass a >> value to f()? "None" doesn't seem to work.. > > I don't understand your question. You can call f(var=1) just fine.
The problem is like the following. def f(var=1): return var*2 def g(): arg = None try: arg = Try_Processing() / 3 + 1 except Nothing_To_Process: pass if arg is None: return f() else: return f(arg) Now in this case you could start by assigning arg the value 1 and eliminate the if test. However that only works if you know the default value for the argument. What he seems to be asking for is if there is an object, (let as call it Default), that would make code like: def f(var=1): Equivallent to: def f(var=Default) if var is Default) var = 1 So that we could write the following without the need of the f's default value. def g(): arg = Default try: arg = Try_Processing() / 3 + 1 except Nothing_To_Process: pass f(arg) -- Antoon Pardon -- http://mail.python.org/mailman/listinfo/python-list