Diez B. Roggisch wrote: > Edward K. Ream wrote: > > > Hi. Presumably this is a easy question, but anyone who understands the > > sax docs thinks completely differently than I do :-) > > > > > > > > Following the usual cookbook examples, my app parses an open file as > > follows:: > > > > > > > > parser = xml.sax.make_parser() > > > > parser.setFeature(xml.sax.handler.feature_external_ges,1) > > > > # Hopefully the content handler can figure out the encoding from the > > # <?xml> > > element. > > > > handler = saxContentHandler(c,inputFileName,silent) > > > > parser.setContentHandler(handler) > > > > parser.parse(theFile) > > > > > > > > Here 'theFile' is an open file. Usually this works just fine, but when > > Filenames are expected to be bytestrings. So what happens is that the > unicode string you pass as filename gets implicitly converted using the > default encoding. > > You have to encode the unicode string according to your filesystem > beforehand.
Not if your filesystem supports Unicode names, as Windows does. Edward's point is that something is (whether by accident or "design") trying to coerce it to str, and failing. -- http://mail.python.org/mailman/listinfo/python-list
