> -----> > Python 2.5 introduced a dictionary type with automatic
> > creation of values,
> > ala Perl:
> >
> > ===============================
> > from collections import defaultdict
> >
> > d = defaultdict(list)
> > for line in fl:
> > k, v = line.strip().split()
> > d[k].append(v)
> >
> > for k,v in d.items():
> > print k, v
> > ===============================
> >
> > Notice that Python is always more strongly typed, so you have
> > to specify a
> > factory function.
>
>
> Yay! Python2.5 fixed my approach to this, I tried
>
> from collections import defaultdict
> f=file('c:\\test.txt')
> lines=f.readlines()
> f.close()
> d=defaultdict(list)
> [ d[l.split()[0]].append(l.split()[1]) for l in lines ]
>
> But, if I try your (to see if I've actually got it right)
>
> For k,v in d.items():
> print k,v
>
> I get
>
> AttributeError: 'list' object has no attribute 'items'
>
Okok, I'm silly.
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