[EMAIL PROTECTED] wrote: > Thanks Robert, > > My previous problem is solved(I was using 'from matplotlib.pylab import > *') but now I am facing another problem. I want to plot the histogram > of eigenvalues calculated and I am using the following code: > _______________________________________________________________________ > import numpy > from matplotlib import pylab > > n=100 > ra = numpy.random > la = numpy.linalg > > A = ra.standard_normal((n,n)) > S = (A + numpy.transpose(A))/(2*n^(1/2))
Note that this line won't do what you think it does. First, one integer divided by another integer returns an integer, so (1/2) == 0. Also, ^ is not exponentiation but bitwise XOR. Use ** for exponentiation. However, in this case, you should use numpy.sqrt(). > eig = la.eigvals(S) > > [N,x]=pylab.hist(eig, 10) # make a histogram > ------------------------------------------------------------------------------------------------------------- > > But again it is giving some error, which is given below: > > File "C:\Documents and Settings\amitsoni\Desktop\New > Folder\wignerpython", line 15, in <module> > [N,x]=pylab.hist(eig, 10) # make a histogram > ValueError: too many values to unpack > > Can anyone help me out with this?? pylab.hist() does not return two values, it returns three. Sorry I didn't catch that earlier. -- Robert Kern "I have come to believe that the whole world is an enigma, a harmless enigma that is made terrible by our own mad attempt to interpret it as though it had an underlying truth." -- Umberto Eco -- http://mail.python.org/mailman/listinfo/python-list