Tuomas schrieb:
> >>> def g(*arg):
> ... return arg
> ...
> >>> g('foo', 'bar')
> ('foo', 'bar')
> >>> # seems reasonable
> ...
> >>> g(g('foo', 'bar'))
> (('foo', 'bar'),)
> >>> # not so good, what g should return to get rid of the outer tuple
>
> TV
Use the following then:
>>> g(*g('foo', 'bar'))
('foo', 'bar')
Otherwise, you would have to check if arg is a 1-tuple consisting of a
tuple and "strip" it out then.
e.g.
>>> def g(*arg):
... return arg[0] if isinstance(arg[0], tuple) else arg
...
>>> g('foo', 'bar')
('foo', 'bar')
>>> g(g('foo', 'bar'))
('foo', 'bar')
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