Dennis Lee Bieber wrote:
> On Sun, 05 Nov 2006 17:42:30 GMT, Tuomas <[EMAIL PROTECTED]>
> declaimed the following in comp.lang.python:
>
>
>
>>I am looking a shorter way to do the above in the case:
>>
>>def g(*arg):
>> return arg
>>
>>def f(*arg):
>> return g(arg)
>>
>>How can g know if it is called directly with (('foo', 'bar'),) or via f
>
>
> Typically, the responsibility should be on the CALLER, not the
> CALLED..
>
>
>>>>def g(*arg):
>
> ... return arg
> ...
>
>>>>def f(*arg):
>
> ... return g(*arg) #<<<<<<<< unpack tuple on call
> ...
>
>>>>f("a", 1, 2)
>
> ('a', 1, 2)
>
>
> Note how f() is calling g() using an * -- Since f() "knows" that its
> arguments were "packed" it calls g() with an unpack marker. Then g()
> gets the arguments via whatever scheme it was coded to use.
>
>
>>>>def f(*arg):
>
> ... return g(arg) #<<<<<<<<<< no tuple unpack
> ...
>
>>>>f("a", 1, 2)
>
> (('a', 1, 2),)
>
>
I fylly agree with tis: "Typically, the responsibility should be on the
CALLER, not the CALLED..". I just don't know how to unpack *arg for
calling g. I can get the len(arg), but how to formulate an unpacked call
g(arg[0], arg[1], ..). Building a string for eval("g(arg[0], arg[1],
..)") seems glumsy to me.
TV
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