[EMAIL PROTECTED] wrote: > Hello, > I am working on a school project that requires me to get the path of a > filename for future treatment. > I've tried getting a file with tkFileDialog.askopenfile. > > > ******************************************** > import tkFileDialog > file = tkFileDialog.askopenfile() > print file > ******************************************** > > > It prints the opened files stuff, but I just can not find how to get > that path as a string. I've searched around google and the present > group, and found no documentation on the file class used with > tkFileDialog. Does someone have a solution for that? > > Thank you > > Christian >
How about: print file.name -- ---------------------------------------------------------------------------- Tim Daneliuk [EMAIL PROTECTED] PGP Key: http://www.tundraware.com/PGP/ -- http://mail.python.org/mailman/listinfo/python-list