The seems good to me, I'll try it out, thanks for the posting.
"Peter Otten 写道: " > Andy wrote: > > > I'm trying to do some predicting work over user input, here's my > > question: > > > > for pattern r'match me', the string 'no' will definitely fail to match, > > but 'ma' still has a chance if user keep on inputting characters after > > 'ma', so how do I mark 'ma' as a possible match string? > > The following may or may not work in the real world: > > import re > > def parts(regex, flags=0): > candidates = [] > for stop in reversed(range(1, len(regex)+1)): > partial = regex[:stop] > try: > r = re.compile(partial + "$", flags) > except re.error: > pass > else: > candidates.append(r) > candidates.reverse() > return candidates > > if __name__ == "__main__": > candidates = parts(r"[a-z]+\s*=\s*\d+", re.IGNORECASE) > def check(*args): > s = var.get() > for c in candidates: > m = c.match(s) > if m: > entry.configure(foreground="#008000") > break > else: > entry.configure(foreground="red") > > > import Tkinter as tk > root = tk.Tk() > var = tk.StringVar() > var.trace_variable("w", check) > entry = tk.Entry(textvariable=var) > entry.pack() > root.mainloop() > > The example lets you write an assignment of a numerical value, e. g > > meaning = 42 > > and colours the text in green or red for legal/illegal entries. > > Peter
-- http://mail.python.org/mailman/listinfo/python-list