Tor Erik Soenvisen <[EMAIL PROTECTED]> wrote: > >(len(['']) is 1) == (len(['']) == 1) => True > >Is this the case for all numbers? I've tried running the following: > >for i in range(10000): > for j in range(10000): > if i != j: > assert id(i) != id(j), 'i=%d, j=%d, id=%d' % (i, j, id >(i)) > >which executes fine. Hence, 0-9999 is okey... But this is a relatively >small range, and sooner or later you probably get two numbers with the same >id... Thoughts anyone?
It has been my experience that virtually every use of the "is" operator (except "is None") is wrong. Now, I fully understand that there are perfectly valid uses for "is", and the standard library contains a few, but for the non-guru casual Python programmer, I think it is safe to say "never use 'is'". -- Tim Roberts, [EMAIL PROTECTED] Providenza & Boekelheide, Inc. -- http://mail.python.org/mailman/listinfo/python-list
