On 12 dic, 17:23, Tom Plunket <[EMAIL PROTECTED]> wrote: > ...at least, I think that I'm having a problem understanding the way > closures work. > > I'm trying to define a function for an object which will take certain > objects from the parent scope at the time that function is defined.
> def CreateTests1(count): > tests = [] > for i in xrange(count): > name = 'Test %d' % i > t = Test(name) > tests.append(t) > > def ExCall(text): > print '%s says, "%s"' % (name, text) > > t.ExternalCall = ExCall > > return tests name, inside ExCall, is a free variable. Python builds a closure including the string whose name is "name" in the enclosing scope. Not the *value* which happens to have at this momment. When you execute ExCall, the reference to name yields its last, current, value. If you want "the value at the moment the function is created" you can use a default argument: def ExCall(text, name=name): ... Your second test works because you don't modify "name" between the original definition and its execution. -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
