[EMAIL PROTECTED] wrote: > Steven D'Aprano wrote: > > Try something like this: > > > > # WARNING: untested > > def run_without_stdout(*args, **kwargs): > > function = args[0] > > args = args[1:] > > savestdout = sys.stdout > > sys.stdout = cStringIO.StringIO() > > result = None > > try: > > result = function(*args, **kwargs) > > finally: > > # don't forget to restore stdout, or you > > # really will regret it... > > sys.stdout = savestdout > > return result > > > Thanks! > > I have tried your method, but I found it didn't work as expected. > > The output produced by the external function couldn't be depressed, > but the "print " statement i wrote in python is depressed. It seems > make cStringIO.StringIO() as a temporary replacement of sys.stdout > has no effect on the external function. > > Here is an example to make myself clear(actually it's modified version > of Steven's code): > > def run_without_stdout(*args, **kwargs): > function = args[0] > args = args[1:] > savestdout = sys.stdout > sys.stdout = cStringIO.StringIO() > print "something" > result = None > try: > result = function(*args, **kwargs) > finally: > # don't forget to restore stdout, or you > # really will regret it... > sys.stdout = savestdout > print "some other thing" > return result > > When run_without_stdout() is called, the "print" statements wrote in python > don't produce output, but function() produces output to the standard output > just as before:( > > I have tried to replace sys.stdout globally with cStringIO.StringIO() > in my program(I mean, make "sys.stdout = cStringIO.StringIO()" as a > globall statement), but it worked just as previous version did.
Perhaps try redirecting sys.stderr instead of sys.stdout. André > > Regards, > > xiaojf
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