Hello: I wrote the code below (much irrelevant code removed). This doesn't quite work. What I wanted it to do was a) Execute function ftimed, which takes a function and a timeout in seconds. b) This will also execute function abort() as a thread. This function just runs for the specified number of seconds and returns. However, before it returns, throws an exception. c) If test() is still running when abort() is finished, ftimed() should catch the exception and return.
It is catching the exception, however it continues running the function. Why does it continue and not return? What am I missing, or is there a better way to implement this (having ftimed() return when the abort-timer time is exceeded? import time, thread, sys thread_finished = "MAX RUN TIME EXCEEDED!" def abort (seconds): start_time = time.time() while ((time.time() - start_time) < seconds): time.sleep(0.01) print "script run time exceeded max_run_time of", seconds, "seconds." raise thread_finished return def test(): i = 0 while (True): time.sleep(1) print "HELLO", i i+=1 def ftimed (func, seconds): thread.start_new_thread (abort, (seconds,)) try: func() except thread_finished: print "Timeout" return ftimed (test, 30) print "Script finished" It presently generates the following output: $ python ./testthread.py HELLO 0 HELLO 1 HELLO 2 HELLO 3 HELLO 4 HELLO 5 HELLO 6 HELLO 7 HELLO 8 HELLO 9 HELLO 10 HELLO 11 HELLO 12 HELLO 13 HELLO 14 HELLO 15 HELLO 16 HELLO 17 HELLO 18 HELLO 19 HELLO 20 HELLO 21 HELLO 22 HELLO 23 HELLO 24 HELLO 25 HELLO 26 HELLO 27 HELLO 28 HELLO 29 script run time exceeded max_run_time of 30 seconds. Unhandled exception in thread started by <function abort at 0x009CEF30> Traceback (most recent call last): File "./testthread.py", line 10, in abort raise thread_finished MAX RUN TIME EXCEEDED! HELLO 30 HELLO 31 HELLO 32 .... Thanks in advance: Michael Yanowitz -- http://mail.python.org/mailman/listinfo/python-list