> def myFunc(listA): > listB = listA > work on & modify listB > return(listB)
def my_func(listA): listB = listA[:] #work on & modify listB return listB Attribution makes the name t the left 'point' to the result of the expression at the right. In your myFunc the expersion at the right is the name listA, at it willl eval to the list that this references. So you will end with to references. In my my_func, the expression at the right is a slicing of the list, from begin to end (listA[:]). Slicing returns a new list, in this example, with the same items of the original list. So you end with two lists, as you wanted. -- EduardoOPadoan (eopadoan->altavix::com) Bookmarks: http://del.icio.us/edcrypt Blog: http://edcrypt.blogspot.com Jabber: edcrypt at jabber dot org ICQ: 161480283 GTalk: eduardo dot padoan at gmail dot com MSN: eopadoan at altavix dot com -- EduardoOPadoan (eopadoan->altavix::com) Bookmarks: http://del.icio.us/edcrypt Blog: http://edcrypt.blogspot.com Jabber: edcrypt at jabber dot org ICQ: 161480283 GTalk: eduardo dot padoan at gmail dot com MSN: eopadoan at altavix dot com -- http://mail.python.org/mailman/listinfo/python-list
