"Marc 'BlackJack' Rintsch" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > In <[EMAIL PROTECTED]>, Tim Arnold wrote: > >> Here's what I do (I need to know the line number). >> >> import os,sys,codecs >> def checkfile(filename): >> f = codecs.open(filename,encoding='ascii') >> >> lines = open(filename).readlines() >> print 'Total lines: %d' % len(lines) >> for i in range(0,len(lines)): >> try: >> l = f.readline() >> except: >> num = i+1 >> print 'problem: line %d' % num >> >> f.close() > > I see a `NameError` here. Where does `i` come from? And there's no need > to read the file twice. Untested: > > import os, sys, codecs > > def checkfile(filename): > f = codecs.open(filename,encoding='ascii') > > try: > for num, line in enumerate(f): > pass > except UnicodeError: > print 'problem: line %d' % num > > f.close() > > Ciao, > Marc 'BlackJack' Rintsch
well, I take it back....that code doesn't work, or at least it doesn't for my test case. but thanks anyway, I'm sticking to my original code. the 'i' came from for i in range. --Tim -- http://mail.python.org/mailman/listinfo/python-list
