Hi, I have a list and I want to find the first element that meets a condition. I do not want to use 'filter', because I want to come out of the iteration as soon as the first element is found. I have implemented it this way, may be, there should be a built in hiding somewhere in the standard libraries?
def exists(iterable, condition): ''' Return the first element in iterble that meets the condition. ''' for x in iterable: if condition(x): return x raise Exception('No element meets the given condition.') >>> exists(xrange(1000), lambda x: x>13) 14 - Suresh -- http://mail.python.org/mailman/listinfo/python-list