"MonkeeSage" <[EMAIL PROTECTED]> writes:
> In your case optimized version, in the second try clause using
> itertools, it should be like this, shouldn't it?
> 
> return t(g.next()[1] for k,g in groupby(s, lambda (i,v): v))

I didn't think so but I can't conveniently test it for now.  Maybe
tonight.  
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