On Mar 1, 7:52 am, "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote: > It seems like this would be easy but I'm drawing a blank. > > What I want to do is be able to open any file in binary mode, and read > in one byte (8 bits) at a time and then count the number of 1 bits in > that byte. > > I got as far as this but it is giving me strings and I'm not sure how > to accurately get to the byte/bit level. > > f1=file('somefile','rb') > while 1: > abyte=f1.read(1)
import struct buf = open('somefile','rb').read() count1 = lambda x: (x&1)+(x&2>0)+(x&4>0)+(x&8>0)+(x&16>0)+(x&32>0)+ (x&64>0)+(x&128>0) byteOnes = map(count1,struct.unpack('B'*len(buf),buf)) byteOnes[n] is number is number of ones in byte n. -- http://mail.python.org/mailman/listinfo/python-list