"Bart Ogryczak" <[EMAIL PROTECTED]> wrote:

> On Mar 5, 11:22 am, [EMAIL PROTECTED] wrote:
>> messagesReceived = dict.fromkeys(("one","two"), {})
> 
> This creates two references to just *one* instance of empty
> dictionary.
> I'd do it like:
> messagesReceived = dict([(key, {}) for key in ("one","two")])
> 
Alternatively use a defaultdict (Python 2.5) and you don't need to know the 
keys in advance:

>>> from collections import defaultdict
>>> messagesReceived = defaultdict(dict)
>>> messagesReceived['one']['123'] = 11111
>>> messagesReceived['two']['121'] = 22222
>>> messagesReceived['two']['124'] = 43333
>>> messagesReceived
defaultdict(<type 'dict'>, {'two': {'121': 22222, '124': 43333}, 'one': 
{'123': 11111}})

-- 
http://mail.python.org/mailman/listinfo/python-list

Reply via email to