"Drew" <[EMAIL PROTECTED]> writes:
> I'm currently writing a toy program as I learn python that acts as a
> simple address book. I've run across a situation in my search function
> where I want to iterate across a filtered list. My code is working
> just fine, but I'm wondering if this is the most "elegant" way to do
> this. Essentially, I'm searching the dict self.contacts for a key that
> matches the pattern entered by the user. If so, I print the value
> associated with that key. A pastie to the method is below, any help/
> advice is appreciated:
If I can decipher your Ruby example (I don't know Ruby), I think you
want:
for name,contact in contacts.iteritems():
if re.search('search', name):
print contact
If you just want to filter the dictionary inside an expression, you
can use a generator expression:
d = ((name,contact) for (name,contact) in contacts.iteritems() \
if re.search('search', name))
print '\n'.join(d) # prints items from filtered dict, one per line
Note that d is an iterator, which means it mutates when you step
through it.
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