a =
[0,1,2,3,4,2,8,9]
# method
1
print [i for i in xrange(len(a)) if
a[i]==2]
def
where(a,val):
return [i for i in xrange(len(a)) if
a[i]==val]
# method
2
print
where(a,2)
[EMAIL PROTECTED] wrote:
On Mar 18, 10:48 pm, [EMAIL PROTECTED] wrote:
vorticitywo:
Is there a function in Python analogous to the "where" function in
IDL?
Python gives very elastic syntax, you can simply do:
data = [0,1,2,3,4,2,8,9]
print [pos for pos, el in enumerate(data) if el==2]
Bye,
bearophile
Thank you both, a little more cumbersome than I expected, but it does
the job! Thanks!
--
Shane Geiger
IT Director
National Council on Economic Education
[EMAIL PROTECTED] | 402-438-8958 | http://www.ncee.net
Leading the Campaign for Economic and Financial Literacy
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adr:Suite 215;;201 N. 8th Street;Lincoln;NE;68508;United States
email;internet:[EMAIL PROTECTED]
title:IT Director
tel;work:402-438-8958
x-mozilla-html:FALSE
url:http://www.ncee.net
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