You don't even need regex.
def
split_seq(seq,size):
# this is sort of the inverse of
flatten
# Source:
http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/425044
return [seq[i:i+size] for i in range(0, len(seq),
size)]
line =
'123456789123456789'
print
split_seq(line,3)
Will that work for you?
[EMAIL PROTECTED] wrote:
hi
how can i use regexp to group these digits into groups of 3?
eg
line 123456789123456789
i have :
pat = re.compile("line\s+(\d{3})" , re.M|re.DOTALL)
but this only gives the first 3. I also tried
"line\s+(\d{3})+"
but also not working.
I need output to be ['123' ,'456','789', '123','456','789', .....]
thanks.
--
Shane Geiger
IT Director
National Council on Economic Education
[EMAIL PROTECTED] | 402-438-8958 | http://www.ncee.net
Leading the Campaign for Economic and Financial Literacy
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