Diez B. Roggisch <[EMAIL PROTECTED]> wrote: > > > > I beleive the convention is when calling an OS function which might > > block the global interpreter lock is dropped, thus allowing other > > python bytecode to run. > > > So what? That doesn't help you, as you are single-threaded here. The > released lock won't prevent the called C-code from taking as long as it > wants. |And there is nothing you can do about that.
I'm assuming that the timeout function is running in a thread... -- Nick Craig-Wood <[EMAIL PROTECTED]> -- http://www.craig-wood.com/nick -- http://mail.python.org/mailman/listinfo/python-list
