On Mar 31, 9:12 pm, "[EMAIL PROTECTED]"
<[EMAIL PROTECTED]> wrote:
> Hi,
>
> I have the following regular expression.
> It works when 'data' contains the pattern and I see 'match2' get print
> out.
> But when 'data' does not contain pattern, it just hangs at
> 're.findall'
>
> pattern = re.compile("(.*)<img (.*?) src=\"(.*?)img(.*?)\"(.*?)",
> re.S)
>
> print "before find all"
>
> match = re.findall(pattern, data)
>
> if (match):
> print "match2"
>
> Can you please tell me why it that?
It doesn't hang when I try it. Why don't you post a complete example
that hangs.
Also, you might consider using exterior single quotes around your
string so that you don't have to escape double quotes inside the
string.
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