On Apr 2, 10:20 pm, Florian Lindner <[EMAIL PROTECTED]> wrote: > Some of the question I have but found answered nowhere: > > I have a feedparser object that was created from a string. How can I trigger > a update (from a new string) but the feedparser should treat the new string > like the same feed (thus setting feed.updated etc.).
Hmm. Do you mean that the feed object should stay the same? Like the difference between "a = [1,2,3]; a = [1,2,3]+[4]" and "a = [1,2,3]; a.append(4)"? I glanced at the parse function in the source code and it looks like it's not directly possible. You could modify it so that the "result" dictionary is optionally given as an argument, so when updating you'd do: feedparser.parse(string, oldFeed). You'd also have to clear the oldFeed object before update. But you might also be able to solve the problem by using an additional layer of indirection. Instead of passing around the "feed" object, you'd pass around a proxy object like this: class Empty: pass proxy = Empty() proxy.feed = feedparser.parse(string) storeProxyForLaterUse(proxy) proxy.feed = feedparser.parse(string2) useStoredProxy() #this would use the updated feed through the proxy Then just use proxy.feed.updated everywhere instead of directly feed.updated. A smarter proxy would automatically translate proxy.updated into proxy.feed.updated so usage would stay as simple as without the proxy. Doing this is quite easy in Python (search for __getattr__ examples). -- http://mail.python.org/mailman/listinfo/python-list