Here is the eigenvalues of KK  I obtained:

 >>> linalg.eigvals(KK)
array([  1.11748411e+05,   3.67154458e+04,   3.41580846e+04,
         2.75272440e+04,   2.09790868e+04,   1.86242332e+04,
         8.68628325e+03,   6.66127732e+03,   6.15547187e+03,
         4.68626197e+03,   3.17838339e+03,   2.84888045e+03,
         1.88279736e+03,   1.32427574e+03,   1.04946287e+03,
         5.79303171e+02,   3.83111876e+02,   4.93826556e-12,
         1.50263232e-12])

You are right. The ratio of max/min eigenvalues is 7.4368432669e+016
Maybe this exceed the of precision of my machine?

Is there any tricks for me to be able to deal with this matrix
correctly with
NumPy?




On Apr 4, 3:58 pm, Robin Becker <[EMAIL PROTECTED]> wrote:
> lancered wrote:
> > Hi dear all,
> ..........
> > matrices are correct.
>
> >        So,  can you tell me what goes wrong?  Is this a bug in
> > Numpy.linalg? How to deal with this situation?  If you need, I can
> > post the matrix I used below, but it is so long,so not at the moment.
>
> .......
>
> presumably the matrix KK is actually some kind of normal matrix obtained from
> the data. So you have say n variables and m observations the data matrix is 
> than
> an n x m real valued thing say D then you want the inverse of something like 
> D'D
> ie an n by n thing. Typically the data D is de-meaned and normalized by the
> column norms so that you end up with a fairly well scaled problem.
>
> A long time ago I used Numeric+python to do exactly this sort of calculation
> with excellent results and the matrices were as large or larger eg 100 x 100 
> and
> above. I don't think the underlying numeric routines have changed that much. 
> If
> your matrix is symmetric then you should certainly be using
>
> Even if you can't post the matrix, perhaps you should indicate how you proceed
> from data to matrix. Another problem is that a large determinant is no 
> guarantee
> of stability for the inversion. If the largest eigenvalue is 10**100 and the
> smallest 10**-200 I probably have an ill determined problem; surprisingly easy
> to achieve :(
> --
> Robin Becker


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