I don't know what is wrong with your code yet, but first you should clean it
up. Either replace those backslashes with forward slashes, or put r before
the first quote in the path string. This prevents special characters from
being evaluated as such.
Second, you should debug a little. Feel free to put print statements in!
correct_settings =
open(r"C:\Python25\Scripts\Output\correct_settings.txt","r")
current_settings = open(r"C:\Python25\Scripts\Output\output.txt","r")
for line in correct_settings:
print "line=", line
for val in current_settings:
print "val=", val
if val == line:
print line, "found." ## please don't concatenate strings in
the print statement! separate them with commas!
break ## You have already found that the same line is in
both files: you don't need to keep searching
correct_settings.close()
current_settings.close()
On 5 Apr 2007 11:01:09 -0700, [EMAIL PROTECTED] <[EMAIL PROTECTED]>
wrote:
What I am trying to do is compare two files to each other.
If the 2nd file contains the same line the first file contains, I want
to print it. I wrote up the following code:
correct_settings = open("C:\Python25\Scripts\Output
\correct_settings.txt","r")
current_settings = open("C:\Python25\Scripts\Output\output.txt","r")
for line in correct_settings:
for val in current_settings:
if val == line:
print line + " found."
correct_settings.close()
current_settings.close()
For some reason this only looks at the first line of the
correct_settings.txt file. Any ideas as to how i can loop through each
line of the correct_settings file instead of just looking at the first?
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