Justin,
Wow! I thought there might be a 'simple' way! thanks so much, you've given
me a lot to chew on.
Jon
__________
J.J. Crump
Dept. of History 353560
University of Washington
Seattle, WA. 98195
On Wed, 11 Apr 2007, Justin Ezequiel wrote:
> On Apr 12, 4:15 am, Jon Crump <[EMAIL PROTECTED]> wrote:
>
>> Is it possible to feed findAll() a list of tags WITH attributes?
>
>>>> BeautifulSoup.__version__
> '3.0.3'
>>>> s = '''<x>\n<z>boo</z>\n<z a="foo" b="bar">hello</z>\n<y
>>>> a="bar">boo</y>\n<y a="foo">hi</y>\n</x>'''
>>>> soup = BeautifulSoup.BeautifulSoup(s)
>>>> def func(tag):
> ... if tag.name not in ('y', 'z'): return False
> ... if tag.name=='y': return tag.get('a')=='foo'
> ... return tag.get('a')=='foo' and tag.get('b')=='bar'
> ...
>>>> soup.findAll(func)
> [<z a="foo" b="bar">hello</z>, <y a="foo">hi</y>]
>>>> def get_func(lst):
> ... def func(tag):
> ... for name, attrs in lst:
> ... if tag.name==name:
> ... for k, v in attrs.items():
> ... if tag.get(k, None)==v: continue
> ... else: return False
> ... else: return True
> ... else: return False
> ... return func
> ...
>>>> func2 = get_func([('y', {'a': 'foo'}), ('z', {'b': 'bar', 'a': 'foo'})])
>>>> soup.findAll(func2)
> [<z a="foo" b="bar">hello</z>, <y a="foo">hi</y>]
>>>>
>
>
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