Michael Bentley <[EMAIL PROTECTED]> writes:
> On Apr 15, 2007, at 6:25 PM, John wrote:
>
> >
> > i have the following code to open a URL address, but can you please
> > tell me how can I check the content type of the url response?
> >
> > Thank you.
> >
> > try:
> > req = Request(url, txdata, txheaders)
> > handle = urlopen(req)
> > except IOError, e:
> > print e
> > print 'Failed to open %s' % url
> > return 0;
> >
> > else:
> > data = handle.read()
>
> Not absolutely sure about this, but try handle.headers.get('Content-
> Type') before the read.
handle.get_header("Content-type")
John
--
http://mail.python.org/mailman/listinfo/python-list
