En Wed, 18 Apr 2007 11:48:06 -0300, pabloski <[EMAIL PROTECTED]> escribió:
> I noted that if I define c.proxy and c.url as costants e.g. c.url = > "http://www.google.com/search?blah blah...." and c.proxy = > "127.0.0.1:8080" it works > > However if I define them as described before pycurl raises the TypeError Python -with its long "batteries included" tradition- comes with two powerful tools for diagnosing problems: print and repr print "c.url", type(c.url), repr(c.url) print "c.proxy", type(c.proxy), repr(c.proxy) -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
