En Fri, 20 Apr 2007 17:48:10 -0300, CSUIDL PROGRAMMEr
<[EMAIL PROTECTED]> escribió:
> On Apr 16, 1:08 pm, Michael Hoffman <[EMAIL PROTECTED]> wrote:
>> CSUIDL PROGRAMMEr wrote:
>> > hi folks
>> > I am new to python. I have a module does call a os.command(cmd) where
>> > cmd is a rpm command.
>> > Instead of using os.command and getting the results on command line ,
>> > i would like to dump the output in a file. Is os.command(cmd >
>> > filename) the most efficient command??
>>
>> I think the best thing to do would be something like this (Python 2.5):
>>
>> from __future__ import with_statement
>> import subprocess
>>
>> with file("test.out", "w") as outfile:
>> subprocess.check_call(["ls", "/etc"], stdout=outfile)
>> --
>> Michael Hoffman
>
>
> but what if i have python which is 2.4??
Omit the with statement:
import subprocess
outfile = open("test.out", "w")
try:
subprocess.check_call(["ls", "/etc"], stdout=outfile)
finally:
outfile.close()
--
Gabriel Genellina
--
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