En Tue, 24 Apr 2007 22:31:59 -0300, Calvin Spealman <[EMAIL PROTECTED]> escribió:
> In the internal API when a C function is called and passed a kwarg > dictionary, is there any case where anything else has a reference to > it? I checked with the following code and it looks like even if you > explicitly pass a dictionary with **kwargs, it still copies the > dictionary anyway. See the Python Reference Manual, 5.3.4 Calls http://docs.python.org/ref/calls.html Unfortunately it does not explicitely *guarantee* it will be a new dictionary. At least the way I read the docs, on a function call like this: def foo(**kwargs): pass d = {'a':1, 'b':2) foo(**d) Python could bind the existing d object to the formal parameter kwargs and still comply with the documented behavior. Some of my own code would break if that happened... :( -- Gabriel Genellina -- http://mail.python.org/mailman/listinfo/python-list
