cjl <[EMAIL PROTECTED]> wrote:
>
>I am using python 2.5.1 on windows. I have the following code:
>
>conn = sqlite3.connect('.\optiondata')
This is unrelated to your question, but you have a slash problem there. \o
doesn't happen to be a valid escape character, but if you had used
"testdata" as the filename, it would have failed.
You should use one of these alternatives:
conn = sqlite3.connect('.\\optiondata')
conn = sqlite3.connect(r'.\optiondata')
conn = sqlite3.connect('./optiondata')
conn = sqlite3.connect('optiondata')
--
Tim Roberts, [EMAIL PROTECTED]
Providenza & Boekelheide, Inc.
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